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What is the total weight of a standard steel plate measuring 4' wide, 8' long, and 1" thick, given that steel weighs 490 lbs/ft3?

  1. 1,206.6 lbs

  2. 1,306.6 lbs

  3. 1,406.6 lbs

  4. 1,506.6 lbs

The correct answer is: 1,306.6 lbs

To determine the total weight of a standard steel plate, we need to calculate the volume of the steel plate first, and then multiply that by the weight of steel per cubic foot. 1. **Calculate the volume of the steel plate**: The dimensions of the plate are as follows: - Width: 4 feet - Length: 8 feet - Thickness: 1 inch. To convert the thickness from inches to feet, we divide by 12. Thus, 1 inch equals \( \frac{1}{12} \) feet. Now we can calculate the volume in cubic feet: \[ \text{Volume} = \text{Width} \times \text{Length} \times \text{Thickness} \] \[ \text{Volume} = 4 \, \text{ft} \times 8 \, \text{ft} \times \frac{1}{12} \, \text{ft} = \frac{32}{12} \, \text{ft}^3 = \frac{8}{3} \, \text{ft}^3 \approx 2.6667 \, \